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Marina86 [1]
3 years ago
5

How do i answer this?

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
4 0
Somesomeone answer this please !!!
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Based on the figure, which pair of triangles is congruent by the Side Angle Side Postulate?
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Answer: Triangle ABC and Triangle ECD


Step-by-step explanation:

In Triangle ABC and Triangle ECD

BD=CD and AD=ED [given in the figure]

∠BDA=∠EDC  [Vertically opposite angles are equal]

⇒ΔABC ≅ ΔECD [By SAS postulate]

SAS postulate or Side Angle Side postulate tells that if two sides and their included angle of one triangle are congruent to two sides and the included angle of another triangle, then the two triangles are congruent.

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What is the factored form of the expression 144x2 - 49?
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Answer:

A

Step-by-step explanation:

Difference of squares: (a^2 - b^2) = (a - b)(a + b)

(144x^2 - 49) = (12x - 7) (12x + 7)

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Two variables are said to be negatively associated if
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Answer:  large values of one variable are associated with small values of the other

Step-by-step explanation:

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Previous Question 24 Next = Question 24 Karli bought 2.5 pounds of beef each week for 4 weeks. She paid $3.30 per pound for beef
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How to use techniques of adding the additive inverse and multiplying by the  Students use algebra to solve equations (of the form px + q = r and p(x + q) = r where p pay with a $10 bill and receive no change, then how much did each bottle of a. If Allen buys 4 uniform shirts at one time, he gets a $10 discount so that the

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PLEASE HELP ME THIS.. I REALLY NEED<br> HELP
Colt1911 [192]

9514 1404 393

Answer:

  5 hours

Step-by-step explanation:

A quick way to look at this is to compare the difference in hourly charge to the difference in 0-hour charge.

The first day, the charge is $3 more than $12 per hour.

The second day, the charge is $12 less than $15 per hour.

The difference in 0-hour charges is 3 -(-12) = 15. The difference in per-hour charges is 15 -12 = 3. The ratio of these is ...

  $15/($3/h) = 5 h

The charges are the same after 5 hours.

__

If you write equations for the charges, they will look like ...

  y1 = 15 + 12(x -1)

  y2 = 3 + 15(x -1)

Equating these charges, we have ...

  15 +12(x -1) = 3 + 15(x -1)

  12x +3 = 15x -12 . . . . . . . . eliminate parentheses

  15 = 3x . . . . . . . . . . add 12-12x

  x = 15/3 = 5 . . . . . . divide by 3

You might notice that the math here is very similar to that described in words, above.

The charges are the same after 5 hours.

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