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FinnZ [79.3K]
2 years ago
10

1. Write out the following expressions:

Mathematics
1 answer:
alexgriva [62]2 years ago
5 0

1b.8×8

c.4×4×4×4

d.6×6×6×6×6×6

e.2×2×2

f.4×4

g.6×6

h.10×10

i.5×5

j.6×6×6

k.12×12

l.10×10×10

2a.5²x³

b.8³

c.4³x⁴

3a.x⁴

b.6⁴s³t³

c.t⁴

4a.81

b.7776

5a.1

b.6561

c.100

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(50 POINTS)
inna [77]
The formula of a function is the rise over run.

The slope would be 2/5.

Hope this helps!
8 0
3 years ago
Simplify 36x^4 42x^7
Alja [10]
The first step to simplify this equation is to multiply the numbers
1512x^{4}×x^{7}
next,, youll multiply the terms with the same base by adding their exponents
1512x^{4+7}
finally,, youll add the numbers together
1512x^{11}
since you cant simplify any further,, the correct answer to your question is 1512x^{11}
let me know if you have any further questions
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4 0
3 years ago
In triangle MNO shown below, segment NP is an altitude:
Effectus [21]

Answer:  C. Definition of an Altitude

Step-by-step explanation:

Given: In triangle MNO shown below, segment NP is an altitude from the right angle.

Let ∠MNP=x

Then ∠PNO=90°-x

Therefore in triangle MNO,

∠MPN=∠NPO =90°  [by definition of Altitude]

[Definition of altitude : A line which passes through a vertex of a triangle, and joins the opposite side forming right angles. ]

Now using angle sum property in ΔMNP

∠MNP+∠MPN+∠PMN=180°

⇒x+90°+∠PMN=180°

⇒∠PMN=180°-90°-x

⇒∠PMN=90°-x

Now, in ΔMNO and ΔPNO

∠PMN=∠PNO=90°-x

and ∠MPN=∠NPO =90°  [by definition of altitude]

Therefore by AA similarity postulate, we have

ΔMNO ≈ ΔPNO

5 0
3 years ago
Find the exact value of cos 120° in simplest form with a rational<br> denominator.
IRINA_888 [86]

Given:

cos 120°

To find:

The exact value of cos 120° in simplest form with a rational  denominator.

Solution:

We have,

\cos 120^\circ

It can be written as

\cos 120^\circ=\cos (90^\circ+30^\circ)

\cos 120^\circ=-\sin 30^\circ             [\because \cos (90^\circ-\theta)=-\sin \theta]

\cos 120^\circ=-\left(\dfrac{1}{2}\right)             [\because \sin 30^\circ=\dfrac{1}{2}]

\cos 120^\circ=-\dfrac{1}{2}

Therefore, the exact value of cos 120° is -\dfrac{1}{2}.

7 0
2 years ago
Can anyone help me please?
Tems11 [23]

The first one

Step-by-step explanation:

the other ones are not statistical

I hope this helps!

6 0
3 years ago
Read 2 more answers
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