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jolli1 [7]
3 years ago
13

3 Which expression is closest in value to 5.66?

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
6 0

Let's consider the standard and usually used value of irrational numbers given in the question.

  • It is asked to see which is closed to 5.66

So, let's see the options:

A) GiveN:

\dfrac{\pi}{2}  + \pi

Let consider π = 3.14

\dfrac{3.14}{2}  + 3.14

1.57 + 3.14

4.71 \: (approx.)

B) GiveN:

2\pi - 1

Here also, let's consider the value be 3.14

2 \times 3.14 - 1

6.28 - 1

5.28  \: (approx.)

C) GiveN:

4 \sqrt{2}

Let's consider the value of √2 be 1.414

4 \times 1.414

5.6516  \: (approx.)

D) GiveN:

8 -  \sqrt{3}

Let's consider the value of √3 be 1.732

8 - 1.732

6.268 \: (approx.)

So, we can see that we have got the approximate value of all the numericals, and the closest to 5.66 is 5.6516 which is the answer of Option C.

So, Correct answer is C

#CarryOnLearning

<u>━━━━━━━━━━━━━━━━━━━━</u>

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Exercise 3.5. For each of the following functions determine the inverse image of T = {x ∈ R : 0 ≤ [x^2 − 25}.
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a. The inverse image of f(x) is f⁻¹(x) = ∛(x/3)

b. The inverse image of g(x) is g^{-1}(x) = e^{x}

c. The inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9

<h3 /><h3>The domain of T</h3>

Since T = {x ∈ R : 0 ≤ [x^2 − 25} ⇒ x² - 25 ≥ 0

⇒ x² ≥ 25

⇒ x ≥ ±5

⇒ -5 ≤ x ≤ 5.

<h3>Inverse image of f(x)</h3>

The inverse image of f(x) is f⁻¹(x) = ∛(x/3)

f : R → R defined by f(x) = 3x³

Let f(x) = y.

So, y = 3x³

Dividing through by 3, we have

y/3 = x³

Taking cube root of both sides, we have

x = ∛(y/3)

Replacing y with x we have

y = ∛(x/3)

Replacing y with f⁻¹(x), we have

So,  the inverse image of f(x) is f⁻¹(x) = ∛(x/3)

<h3>Inverse image of g(x)</h3>

The inverse image of g(x) is g^{-1}(x) = e^{x}

g : R+ → R defined by g(x) = ln(x).

Let g(x) = y

y =  ln(x)

Taking exponents of both sides, we have

e^{y} = e^{lnx} \\e^{y} = x

Replacing x with y, we have

y = e^{x}

Replacing y with g⁻¹(x), we have

So, the inverse image of g(x) is g^{-1}(x) = e^{x}

<h3>Inverse image of h(x)</h3>

The inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9

h : R → R defined by h(x) = x − 9

Let y = h(x)

y = x - 9

Adding 9 to both sides, we have

y + 9 = x

Replacing x with y, we have

x + 9 = y

Replacing y with h⁻¹(x), we have

So, the inverse image of <u>h</u>(x) is h⁻¹(x) = x + 9

Learn more about inverse image of a function here:

brainly.com/question/9028678

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