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andrew-mc [135]
3 years ago
11

Please, Help with this MATH question.

Mathematics
2 answers:
hammer [34]3 years ago
6 0
Y in the second equation
fiasKO [112]3 years ago
4 0
The x at the second one. I hope you are help
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PLEASE HELP!!! Sarah had a balance of $155 in her bank account at the start of the week. She withdrew $65.50 on Monday, $23.25 o
Firdavs [7]

Answer:

155.00-65.50-23.25-26.45+165.30

Step-by-step explanation:

5 0
3 years ago
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The value of a car with an initial purchase price of $15,250 depreciates by 16% per year. How much is the car worth after 6 year
Scrat [10]

Answer:

$13842.43

Step-by-step explanation:

Given data

Value of car=$15,250

Rate of depreciation= 16%

Time = 6 years

We can use the exponential function below to model the value of the car after 6 years

v(t)= a(r)^x

But r= 1-0.016----------Because the value is depreciating

a=15,250  

r=0.016  

x=6

Substitute

v(t)= 15250(1-0.016)^6

v(t)=  15250(0.984)^6

v(t)=  15250*0.9077

v(t)= $13842.43

Hence the value will be $13842.43 after 6 years

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3 years ago
Who wants 35 points????
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What is the equation of the line through (4, 2) and (0, -2)?
Kamila [148]
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4 years ago
What is the image of (x, y) after a translation of 3 units right and 7 units down?
fenix001 [56]

Translation involves changing the position of a shape.

The image of point (x,y) after a translation of 3 units right and 7 units down is: \mathbf{(x - 3,y - 7)}

The point is given as: (x,y)

The rule of translation 3 units right is:

\mathbf{(x,y) \to (x-3,y)}

The rule of translating 7 units down is:

\mathbf{(x,y) \to (x,y - 7)}

So, we have:

\mathbf{(x - 3,y) \to (x - 3,y - 7)}

Hence, the image of point (x,y) after a translation of 3 units right and 7 units down is: \mathbf{(x - 3,y - 7)}

Read more about translations at:

brainly.com/question/12463306

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3 years ago
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