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Black_prince [1.1K]
2 years ago
7

Which distance measures 7 units?

Mathematics
1 answer:
GrogVix [38]2 years ago
3 0

Answer:

M to P

Step-by-step explanation:

It goes 7 hops from -1 to 6

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3 + 2x = y Given x = 4 y =
wel

Answer:

y = 11

Step-by-step explanation:

Plug 4 in for x.

3 + 2(4) = y

Multiply.

3 + 8 = y

Simplify.

11 = y

7 0
2 years ago
Read 2 more answers
What 2/9rounded to the nearest whole number
Arte-miy333 [17]
The answer is 3 because if you were to round 2.9 the next whole up from that is 3
4 0
2 years ago
Solve this .....................​
ycow [4]

Answer:

Step-by-step explanation:  3root5x^2 + 25x - 10root5 = 0

3xroot5 + 25x - 10root5 = 0      [ root x^2 = x]

28x root5 = 10 root5         [ -10root5 turns to 10 root5 when transferred to RHS]

28x root 5/root5 =10

28x=10

x = 10/28

x = 0.35

Hope it helped u,

pls mark as the brainliest

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5 0
3 years ago
Find the perimeter of pentagon STUVW WITH VERTICES S(0,0) T(3,-2) U(2,-5) V(-2,-5) W(-3,-2)
andrew11 [14]
Use the distance formula.

\sqrt{( x_{2} - x_{1} )^2 + (y_{2} - y_{1})^2}

 
Points S and W.
\sqrt{(3)^2 + (2)^2}

\sqrt{9+4}

\sqrt{13}

~3.6

Points S and T
\sqrt{(3 - 0)^2 + (-2 - 0)^2}

\sqrt{(3)^2 + (-2)^2}

\sqrt{9+4}

\sqrt{13}

~3.6

Points T and U
\sqrt{(3 - 2)^2 + (-2 + 5)^2}

\sqrt{(1)^2 + (3)^2}

\sqrt{1+9}

\sqrt{10}

~3.1

Points U and V
\sqrt{(2+2)^2 + (-5 + 5)^2}

\sqrt{(4)^2 + (0)^2}

\sqrt{16}

~4

Points V and W
\sqrt{(-2+3)^2 + (-5 + 2)^2}

\sqrt{(1)^2 + (-3)^2}

\sqrt{2+9}

\sqrt{11}

~3.3

Add all these together.

3.3 + 3.1 + 4 + 3.1 + 3.6
≈17
4 0
3 years ago
1
Marianna [84]

Answer:

  B. {16, 19, 20}

Step-by-step explanation:

The <em>triangle inequality</em> requires for any sides a, b, c you must have ...

  a + b > c

  b + c > a

  c + a > b

The net result of those requirements are ...

  • the sum of the two shortest sides must be greater than the longest side
  • the length of the third side lies between the difference and sum of the other two sides

__

If we look at the offered side length choices, we see ...

  A: 8+11 = 19 . . . not > 19; not a triangle

  B: 16+19 = 35 > 20; could be a triangle

  C: 3+4 = 7 . . . not > 8; not a triangle

  D: 5+5 = 10 . . . not > 11; not a triangle

The side lengths {16, 19, 20} could represent the sides of a triangle.

_____

<em>Additional comment</em>

The version of triangle inequality shown above ensures that a triangle will have non-zero area.

The alternative version of the triangle inequality uses ≥ instead of >. Triangles where a+b=c will look like a line segment--they will have zero area. Many authors disallow this case. (If it were allowed, then {8, 11, 19} would also be a "triangle.")

4 0
2 years ago
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