Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
Answer:
i think its 6
Step-by-step explanation:
im so sorry if its wrong im pretty sure it is
How you would solve it is by 8 multiplied by 4.
The formula B*H
So the answer is 32cm squared.
Answer:.
x greater than or equal to -8
Step-by-step explanation:
x+22-13x≥118
Collect like terms
x-13x≥118-22
-12x≥96
Divide both sides by -12
-12x/12≥96/-12
x≥96/-12
x≥-8
The answer is x greater than or equal to -8
