Hey there!
Markup is the percentage that the cost of an item is increased.
For example, if a company bought a pair of headphones that costed $100 and they sold it for $150, the markup was 50%, since half of the original cost was added. if the markup were 100% it would have been sold for $200, since it added 100% of the original.
I hope this helps!
The area of a parallelogram is just:
A=bh, we are given b=3ft, so b=36in and A=324in^2 so
324=36h dividing both sides by 36
h=9
So the height is 9 inches.
Ok
A=bh
plug in
126 square meters=6b
126/6 6/6
21=b
base length=21meters
1)
1 = 38
2 = 38
3 = 38
4 = 38
2)
1 = 32
2 = 90
3 = 58
4 = 32
Let me know if I'm wrong.
Answer:
Roots are not real
Step-by-step explanation:
To prove : The roots of x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0 are real for all real values of k ?
Solution :
The roots are real when discriminant is greater than equal to zero.
i.e. b^2-4ac\geq 0b
2
−4ac≥0
The quadratic equation x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0
Here, a=1, b=1-k and c=k-3
Substitute the values,
We find the discriminant,
D=(1-k)^2-4(1)(k-3)D=(1−k)
2
−4(1)(k−3)
D=1+k^2-2k-4k+12D=1+k
2
−2k−4k+12
D=k^2-6k+13D=k
2
−6k+13
D=(k-(3+2i))(k+(3+2i))D=(k−(3+2i))(k+(3+2i))
For roots to be real, D ≥ 0
But the roots are imaginary therefore the roots of the given equation are not real for any value of k.