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3 years ago

If you vertically compress the absolute value parent function, f(x) = |xl, by a

1 answer:

6 0

The new function would be 3lxl

If y=f(x), then the transformed function will be y=3f(x) because the compression affects the y value, and so the function becomes y=3lxl

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Kay [80]

I d o n t k n o w s o g o o d l u c k

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3 years ago

Read 2 more answers

A function f has derivatives of all orders for all real numbers, x. Assume f(2) = −3, f ′(2) = 5, f ″(2) = 3 and the third deriv

nadezda [96]

The Taylor polynomial would be

$T_3(x)=f(2)+f'(2)(x-2)+\dfrac{f''(2)}2(x-2)^2+\dfrac{f'''(2)}6(x-2)^3$

$T_3(x)=-3+5(x-2)+\dfrac32(x-2)^2-\dfrac43(x-2)^3$

Then

$f(1.5)\approx T_3(1.5)=-\dfrac{119}{24}\approx-4.96$

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3 years ago

1. What operations would you use in order to solve 3x – 4 = 26. Please write the operations in the order you would use them.

alex41 [277]

1. add the 4 to both sides

2. divide both sides by 3

3 0

3 years ago

Find the missing length. The triangles in each pair are similar.

oee [108]

Answer:

Step-by-step explanation:

This a not so simple ratio problem:

MN is to LN as TN is to UN as MT is to LU

MN/LN = TN/UN = MT/ LU trying to find LU

88 / (? + 32) = (88-56)/32 = 56/?

= 32 / 32 = 56 / ?

1 = 56 / ?

? = 56

88 / (56 +32) = 1 This must be an Isosceles triangle and UT bisects

LN and MN

5 0

3 years ago

You make a tape of your friend's three favorite TV shows: a comedy, a drama and a reality

vodka [1.7K]

Answer:

comedy = 2

drama = 4

reality = 1

Step-by-step explanation:

comedy = 30min

denote as "c"

drama = 60min

denote as "d"

reality = 60min

denote as "r"

write in English

(30min of c) + (60 min of d) + (60min of r) totals to 360 min

translate to mathematics

(30c) + (60d) + (60r) = 360

we also know that there is a total of seven episodes

so we can say

c + d + r = 7

and we also know that there are twice as many episodes of drama as there is of comedy so it can be said that

d = 2c

now there is a system of equations

30c + 60d + 60r = 360

c +d + r = 7

d = 2c

all we know have to do is simplify and solve

substitute in the second equation, into the first

c + d + r = 7

d = 2c

c + 2c + r = 7

simplify

3c + r = 7

r = 7 - 3c

substitute this into the first equation

d = 2c

r = 7 -3c

30c + 60d + 60r = 360

30c + 60(2c) + 60(7 - 3c) = 360

distribute

30c + 120c + 420 - 180c = 360

simplify

-30c + 420 = 360

-420 -420

-30c = -60

c = 2

substitute back into the other equations and solve

d = 2c

d = 2 *2

d = 4

r = 7 - 3c

r = 7 - 3 * 2

r = 7 -6

r = 1

4 0

3 years ago