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solong [7]
4 years ago
7

How many solutions does this linear equation have? Y= 2x - 5

Mathematics
2 answers:
Alex_Xolod [135]4 years ago
6 0
Y = 2x - 5...slope = 2, y int = -5

-8x - 4y = -20
-4y = 8x - 20
y = -2x + 5....slope = -2, y int = 5

different slopes, different y int's means 1 solution <==

** same slope, same y int = infinite solutions
** same slope, different y int's = no solutions

OlgaM077 [116]4 years ago
6 0

Answer:

Our given system has exactly one solution.

Step-by-step explanation:

We have been given a system of equation. We are asked to find the number of solutions for our given system.

First of all, we will convert our second equation in slope-intercept form of equation as shown below:

-8x-4y=-20

Upon dividing both sides of our equation by -4, we will get:

\frac{-8x}{-4}-\frac{4y}{-4}=\frac{-20}{-4}

2x+y=5

2x-2x+y=-2x+5

y=-2x+5

Upon comparing our both equations, we can see that they have different slopes and different y-intercepts, therefore, they will have exactly one solutions as they will intersect at one place.

Upon looking at our attachment, we can see that our explanation is correct.

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