Question

Snefuru’s north pyramid at Dahshur, Egypt, is shown. It’s square base has a side length of 220 m. The height of the pyramid is 105 m. Determine it’s surface area.
The answer is 115,324 m^2, show how you got your answer please. :))

Answer 1

Answer: 115,324 m^2

Step-by-step explanation:

To find the surface area, we need height of the triangle face of the pyramid. We are given the height of the pyramid itself (105 m). To find the height of the triangle face, we have to use the Pythagorean theorem (a^2 + b^2 = c^2).

In the diagram attached, the height of the triangle face is the hypotenuse of the blue triangle: 110^2 + 105^2 = c^2 where c = about 152 m (ROUNDED)

Now that we have the height of the triangle face, we can use the triangle area formula: 1/2(base)(height) to find the area of one of the triangle faces.

1/2 (220)(152) = 16,720 m^2

Since there are four triangle faces, we need to multiply this number by four.

16,720(4) = 66880 m^2.

Now we just have to add this to the area of the square base which is:

(220)(220) = 48400 m^2

66880 + 48400 = 115,200 m^2 (which is very close to the answer provided - if 152 wasn't rounded, 115,324 would be your answer)