Answer:
The width of the red tile would be
inches.
Step-by-step explanation:
Given blue tile has a length of
inches, and a width of
inches.
Also, length of similar tile is
inches.
Let us assume
as the width of red tile.
It is given in the question that both tiles are similar.
So, their area will be the same.
Area of blue tile would be ![4.25\times 6.75=28.6875\ inch^2](https://tex.z-dn.net/?f=4.25%5Ctimes%206.75%3D28.6875%5C%20inch%5E2)
Area of red tile would be ![12.75\times x](https://tex.z-dn.net/?f=12.75%5Ctimes%20x)
The area of blue tile would be equal to area of red tile.
![28.6875=12.75\times x](https://tex.z-dn.net/?f=28.6875%3D12.75%5Ctimes%20x)
![\frac{28.6875}{12.75}=x\\\\x=2.25](https://tex.z-dn.net/?f=%5Cfrac%7B28.6875%7D%7B12.75%7D%3Dx%5C%5C%5C%5Cx%3D2.25)
So, the width of the red tile would be
inches.