Answer:
- 5
- 6
- 6
- 5
Remember the decimal <em>hundredths</em> rounding ruleset.
- If a decimal is below .50, round down.
- If a decimal is .50, round up.
- If a decimal is above .50, round up.
View this array below to get a better image.
![\left[\begin{array}{ccc}0.49(down)&0.50(up)&0.51(up)\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0.49%28down%29%260.50%28up%29%260.51%28up%29%5Cend%7Barray%7D%5Cright%5D)
So, for example, if you had 6.51, you would round that up to 7, and if you had 8.47, you would round that to 8
14. -6m²-2m+1
15. 14x-24
16.3b²
17.14p+7
do you need the steps?
Answer:
fgscgethre 4 fsvcadc 14143
Step-by-step explanation:
i just tryna get point lol srry
Answer:
C. y + 3 = ¼(x + 4)
Step-by-step explanation:
✔️Find the slope of the given line:
Slope = ∆y/∆x = -(4/1) = -4
The line that is perpendicular to the given line on the graph would have a slope that is the negative reciprocal of -4.
Thus, the slope of the line that is perpendicular to the line on the graph would be ¼.
m = ¼.
Since the line passes through (-4, -3), to write the equation in point-slope form, substitute a = -4, b = -3, and m = ¼ into y - b = m(x - a)
Thus:
y - (-3) = ¼(x - (-4))
y + 3 = ¼(x + 4)
Probably a for plot, because It shows how close each value is, or if the values are all scattered around. it gives you a more accurate ways of seeing how close the data is. hope this helped
