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Mariana [72]
2 years ago
13

Its on the picture, plz go fast

Mathematics
1 answer:
Naily [24]2 years ago
7 0

Answer:

Elimination

Step-by-step explanation:

You would not do substitution since it would not work so you do elimination since the 4y and -4y eliminate then you just solve for it.

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If AB=50, what are AC and CB?
KiRa [710]
X=6
AC= 14
CB= 36
hope this helps!!
6 0
3 years ago
How do you solve 32 - 6x = 53?
katrin2010 [14]

\large\boxed{x=-\frac{7}{2}}

To solve for x, we need to isolate it on one side of the equation.

The most important part of this is knowing that whatever we do to one side of the equation, we must also do to the other.

Subtract 32 from both sides of the equation.

\begin{aligned}32-32-6x&=53-32\\-6x&=21\end{aligned}

Divide both sides of the equation by -6.

\begin{aligned}\frac{-6x}{-6}&=\frac{21}{-6}\\x&=\boxed{-\frac{7}{2}}\end{aligned}

7 0
2 years ago
Read 2 more answers
What is the slope of the line for BOTH graphs? Are the slopes the same or different?
Y_Kistochka [10]

Answer:

both are -10

Step-by-step explanation:

#1

x1 y1  x2 y2

1.5 180  6 135

(Y2-Y1) (135)-(180)=   -45  ΔY -45

(X2-X1) (6)-(1.5)=    4.5  ΔX 4.5

slope= -10          

B= 195          

Y =-10X +195

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~    

#2

x1 y1  x2 y2

1 175  8 105

   

(Y2-Y1) (105)-(175)=   -70  ΔY -70

(X2-X1) (8)-(1)=    7  ΔX 7

slope= -10          

B= 185          

Y =-10X +185    

7 0
3 years ago
Y= 2.5x+ 5.8 when x = 0.6 pls find the function
adoni [48]
You’d plug in the 0.6 for x. so you’d multiple 0.6 times 2.5 then you’d get 1.5 then you’d add 1.5 plus 5.8 and get 7.3
6 0
3 years ago
30 POINTS I WILL GIVE U BRAINLIEST AND THANKS AND 5 STARS please help this is very important this is a big part of my grade
mars1129 [50]

Answer:

1.\:2^x=64, x=\boxed{6},\\2.\:x=\left(\frac{2}{3}\right)^3,x=\boxed{\frac{8}{125}}\\3.\:3\cdot (3^4)=3^x, x=\boxed{5}\\4.\:\frac{16}{25}=x^2,x=\boxed{\frac{4}{5}},

Step-by-step explanation:

1.\\\\2^x=64,\\\log 2^x=\log64,\\x\log 2=\log 64,\\x=\frac{\log 64}{\log 2}=\boxed{6}

2.\\x=\left(\frac{2}{5}\right)^3=\frac{2^3}{5^3}=\boxed{\frac{8}{125}}

3. This problem incorporates an exponent property.

Exponent property used: a^b\cdot a^c=a^{(b+c)}, yielding an answer of \boxed{5}

4.\\\\\frac{16}{25}=x^2,\\x=\sqrt{\frac{16}{25}}=\frac{\sqrt{16}}{\sqrt{25}}=\boxed{\frac{4}{5}}

3 0
3 years ago
Read 2 more answers
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