3 years ago

Can someone help me with this problem?

Mathematics

1 answer:

stepladder [879]3 years ago

4 0

Answer:

True

Step-by-step explanation:

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Solve for z : <img src="https://tex.z-dn.net/?f=-7%20%3D%20%5Cfrac%7Bz%7D%7B-6%7D" id="TexFormula1" title="-7 = \frac{z}{-6}

aivan3 [116]

Answer:

42 = z

Step-by-step explanation:

$-7=\frac{z}{-6}$ Multiply both sides by -6 to get z by itself

42 = z

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Destiny’s bank account has a balance of $612.75 before she starts spending money. She makes the following transactions: (See tab

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Answer:

she is overdrawn by $-5.68

Step-by-step explanation:

so A no she is overdrawn already

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3 years ago

A recipe for cookies calls for 2/3 cups of sugar per batch Atlanta use 4 cups of sugar to multiply batches of cookies how many b

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Evaluate the expression when m=-3. 2 m” +8m-7 HELP ASAP

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4 years ago

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A recent study stated that if a person chewed gum, the average number of sticks of gum he or she chewed daily was 8. Researcher

konstantin123 [22]

Answer:

The average number of sticks of gum a person chewed daily was greater than 8.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 8

Sample mean, $\bar{x}$ = 9

Sample size, n = 36

Alpha, α = 0.05

Population standard deviation, σ = 1

First, we design the null and the alternate hypothesis

$H_{0}: \mu \leq 8\text{ gums}\\H_A: \mu > 8\text{ gums}$

We use one-tailed z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{9 - 8}{\frac{1}{\sqrt{36}} } = 6$

Now, $z_{critical} \text{ at 0.05 level of significance } = 1.64$

Since,

$z_{stat} > z_{critical}$

We fail to accept the null hypothesis and reject the null hypothesis. We accept the alternate hypothesis.

Thus, the average number of sticks of gum a person chewed daily was greater than 8.

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4 years ago