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natulia [17]
3 years ago
13

Add h to g, then divide 10 by the result

Mathematics
2 answers:
iogann1982 [59]3 years ago
8 0

Here variables are

  • h and g

Add h and g means to do addition so we use + sign

\\ \sf\longmapsto h+g

Divide 10 by the result:-

\\ \sf\longmapsto \dfrac{10}{h+g}

Assoli18 [71]3 years ago
3 0

Your expression will be:

-Double h = multiply h by 2

-Divide g  by the result (2h)

g/(2h)

Hope this helps :)

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olganol [36]
The answer is 908. Your welcome.
3 0
3 years ago
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Assortative mating is a nonrandom mating pattern where individuals with similar genotypes and/or phenotypes mate with one anothe
scZoUnD [109]

Answer:

a) P(male=blue or female=blue) = 0.71

b) P(female=blue | male=blue) = 0.68

c) P(female=blue | male=brown) = 0.35

d) P(female=blue | male=green) = 0.31

e) We can conclude that the eye colors of male respondents and their partners are not independent.

Step-by-step explanation:

We are given following information about eye colors of 204 Scandinavian men and their female partners.

              Blue    Brown     Green    Total

Blue        78         23            13          114

Brown     19         23            12          54

Green     11           9             16          36

Total      108       55            41          204

a) What is the probability that a randomly chosen male respondent or his partner has blue eyes?

Using the addition rule of probability,

∵ P(A or B) = P(A) + P(B) - P(A and B)

For the given case,

P(male=blue or female=blue) = P(male=blue) + P(female=blue) - P(male=blue and female=blue)

P(male=blue or female=blue) = 114/204 + 108/204 − 78/204

P(male=blue or female=blue) = 0.71

b) What is the probability that a randomly chosen male respondent with blue eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=blue) = 78/114

P(female=blue | male=blue) = 0.68

c) What is the probability that a randomly chosen male respondent with brown eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=brown) = 19/54

P(female=blue | male=brown) = 0.35

d) What is the probability of a randomly chosen male respondent with green eyes having a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=green) = 11/36

P(female=blue | male=green) = 0.31

e) Does it appear that the eye colors of male respondents and their partners are independent? Explain

If the following relation holds true then we can conclude that the eye colors of male respondents and their partners are independent.

∵ P(B | A) = P(B)

P(female=blue | male=brown) = P(female=blue)

or alternatively, you can also test

P(female=blue | male=green) = P(female=blue)

P(female=blue | male=blue) = P(female=blue)

But

P(female=blue | male=brown) ≠ P(female=blue)

19/54 ≠ 108/204

0.35 ≠ 0.53

Therefore, we can conclude that the eye colors of male respondents and their partners are not independent.

7 0
3 years ago
Please Help Me On This
anastassius [24]

Answer:

X2 = (-2, 1), W2 = (-4, 1), Y2 = (4, -2), Z2 = (-3, 2)

Step-by-step explanation:

First, flip across the y-axis:

Coordinates: X1 = (2, -1), W1 = (4, -1), Y1 = (2, -4), and Z1 = (3, -2)

Then, rotate 180 degrees counterclockwise:

Coordinates: See above

5 0
3 years ago
Which expression is equivalent to this expression?
saw5 [17]

Answer:

3h-4.5

Step-by-step explanation:

3/4(4h-6)

12/4h-18/4

3h-4.5

hope it's helpful ❤❤❤❤❤❤

THANK YOU.

#

4 0
3 years ago
Please Help Me With This.
Romashka-Z-Leto [24]

Answer:

A is $0.45 B is 2 ounces

Step-by-step explanation:

A when you divide the cost by the ounces or $5.40 by 12 ounces you get $0.45 per ounce.

B $0.45 times 2 equals 90 cents and you cannot go over 1 dollar.

C you should be to do along with D with this information.

5 0
3 years ago
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