Answer:
a. 8,953.5 seconds
b. 14,400 seconds (check note)
Step-by-step explanation:
a.
y=-4x
y=-35814 (negative because this is underwater)
-35814=-4x
8953.5
The model suggests it would take 8,953.5 seconds for DeepSea Challenger to reach the bottom (2.487083333 hours, or about 2 hours and 30 minutes).
b.
y=4x
x=3600 (positive because the vessel is rising)
4(3600)
14400
It took 14,400 seconds for the DeepSea Challenger to ascend to the surface.
[also note: I'm not sure if the second question is asking for how many seconds it takes to ascend to the surface with reference to the 4 seconds in the previous question (which is how I answered part b) or if it's asking how many seconds 1 hour is, and in that case. the answer is 3,600 seconds. I hope this helps and sorry if it's unclear!]
Answer:
The answer is the last one.
Step-by-step explanation:
When you do the others , they are step by step but when you do the last one, its just one step, which is -100.
Hope this helps :)
Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need
to minimize the area A=x*y
we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2
so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4
find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]
for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in
(y)=[722/(x-4)]+2
y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in
the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in
The circumference of the circle is 75.36 cm.
Diameter of the circle is 24 cm,
- Step 2: Formula used and calculation:
Circumference of the circle is 
.
So, Radius, r = 24/2 = 12 cm.
Now, Putting the value in the above formula, we get
2 × 3.14 ×12 = 3.14 × 24 = 75.36 cm.
Hence, the circumference of the circle is 75.36 cm.
Learn more about circumference of the circle, refer:
brainly.com/question/23964435
