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2 years ago

Simplest form please!

Mathematics

1 answer:

deff fn [24]2 years ago

6 0

Answer:

Step-by-step explanation:

Call the given fraction x

x = 0.436363636....

Multiply the given fraction by 1000

1000 x = 436.3636363636 ....

10 x = 4.363636.... is the original number multiplied by 10

990x = 432 the 0.36363636 ... cancels out of both of them

990x = 432 Divide by 990

x = 432 / 990

x = 216 / 495

I think that is about as simple as you can get it.

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3 years ago

Simplify each of the following:

Zepler [3.9K]

Answer:

√25 + √50 - √24 + √49 =
5 + 5√2 - 2√6 + 7 =
12 + 5√2 - 2√6

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3 years ago

Read 2 more answers

In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= root 2 cm.

Nata [24]

Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.

Let AD=x, Since given AB=3

AD+DB=3

x+DB = 3

DB = 3-x

Since ΔBCD is rght angle triangle, let's apply Pythagoras theorem

$BC^{2} = DB^{2} +CD^{2}$

$BC^{2} = (3-x)^{2} +(\sqrt{2} )^{2}$

$BC^{2} =(3-x)^{2} +2$

Since given AD=BC,let us plugin BC=x in above step.

$x^{2} =(3-x)^{2} +2$

$x^{2} =9-6x+x^{2} +2$

6x=11

x= $\frac{11}{6}$

Now we know AD=x= $\frac{11}{6}$ and given CD=√2.

Let us apply Pythagoras theorem for ΔACD

$AC^{2} =AD^{2} +DC^{2}$

$AC^{2} = (\frac{11}{6} )^{2} +(\sqrt{2} )^{2}$

$AC^{2} =\frac{193}{36}$

$AC=\sqrt{\frac{193}{36} }$ = 2.315cm

3 0

3 years ago

Evaluate -15a (-3) for a= 2 and b=-3<br> A.) 5/24 B.) -5/24 C.) -1080 D.) -40/3

zloy xaker [14]

Hhjhhhu did I need ooo 40

4 0

3 years ago

Please help me!!! :(

PSYCHO15rus [73]

Answer:

$15.75x^{10}y^{19}$

Step-by-step explanation:

To find the 5th term in the expansion, we first will need to apply the binomial theorem. I have attached an image of the binomial theorem formula due to not being able to type it.

After applying the binomial theorem and simplifying, you should get:

$512x^{18}y^{27}-576x^{16}y^{25}+288x^{14}y^{23}-84x^{12}y^{21}+\frac{63x^{10}y^{19}}{4}-\frac{63x^8y^{17}}{32}+\frac{21x^6y^{15}}{128}-\frac{9x^4y^{13}}{1024}+\frac{9x^2y^{11}}{32768}-\frac{y^9}{262144}$

Our 5th term here is: $\frac{63x^{10}y^{19}}{4}$ which is equal to $15.75x^{10}y^{19}$

~Hope this helps! Sorry if my answer is confusing at all, it's pretty difficult to explain.~

4 0

2 years ago