The correct answer is d hope i could help
Answer:
Answer:
Stabilizer with area = 14 cm².
Step-by-step explanation:
Area of the wing = 101.25 cm²
Rule of the thumb is that area of stabilizer must be about 1/6 to 1/8 of the area of wing. So, first we calculate 1/6 of the area of the wing and 1/8 of the area of the wing. Area of stabilizer must be in between these two numbers.
1/6 of the area of wing = \frac{1}{6} \times 101.25 = 16.87561×101.25=16.875
1/8 of the area of wing = \frac{1}{8} \times 101.25 = 12.65681×101.25=12.656
This means, the area of horizontal stabilizer must be in between 12.656 cm² and 16.875 cm². From the given options only one option lies in between these two numbers and that is 14 cm²
Therefore, area of a good stabilizer design from the given options would be 14 cm²
Answer:
The vertical asymptote is r = 0.
The intensity is undefined at the source.
The horizontal asymptote is I = 0.
As the distance from the source increases, the intensity goes to zero.
The intensity decreases as the distance increases.
Explanation:
