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yaroslaw [1]
2 years ago
5

two piers, a and b, are located s km away from each other along a river. a motorboat, with a speed of v km/hour in still water,

is cruising between the two piers. How much time t (in hours) will the motorboat need to get from pier a to pier b and back, if the speed of the current is 5km/hour? find t if: s=105 v=40
Mathematics
1 answer:
Lyrx [107]2 years ago
3 0

Answer:

speed in still water is v=40 speed of current

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<h3>♫ :::::::::::::::::::::::::::::: // Hello There ! //  :::::::::::::::::::::::::::::: ♫</h3>

➷  Find the rate per hour

5 hours = 3 lawns

1 hour = 3/5 lawns

Multiply this value by 30 to get the answer:

3/5 x 30 = 18

She can rake 18 lawns.

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4 years ago
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ollegr [7]
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6 0
3 years ago
PLS ANWER ASAP!! person with correct answer will be marked brainliest
iogann1982 [59]

Answer:

62 degrees since there are supplementary angles

Step-by-step explanation:

∠PQO= 180 degrees - 118 degrees

∠PQO= 62 degrees is the answer.

4 0
3 years ago
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5/8 is greater then 7/12.

Step-by-step explanation:

Find the least common denominator or LCM of the two denominators:

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For the 1st fraction, since 8 × 3 = 24,

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Likewise, for the 2nd fraction, since 12 × 2 = 24,

7/12= 7x2/12x2=14/24

Since the denominators are now the same, the fraction with the bigger numerator is the greater fraction

15/24>14/24 or 5/8>7/12

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Answer:

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