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Masteriza [31]
2 years ago
7

PLEASE FILL IN BLANK I WILL MARK AS BRAINLIEST

Mathematics
1 answer:
zvonat [6]2 years ago
6 0

Answer:

\sqrt[3]{x}

x^3

is

Step-by-step explanation:

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In the given table we note that there are six clear subintervals: [0, 0.5], [0.5, 1.0], [1.0, 1.5], [1.5, 2.0], [2.0, 2.5], and
gizmo_the_mogwai [7]

Answer:

The width is 0.5.

Δt, can be stated as follows = 0.5

Step-by-step explanation:

The change is 0.5

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2 years ago
Find absolute max and min on a given interval calculator
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Min {sin(x) | 0 is les than or equal to x less than or greater than or equal to 2 pie = -1 at x = 3 pie over 2

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3 years ago
<img src="https://tex.z-dn.net/?f=-3%2Fz%2B7%2F4z%3D5%2Fz-25" id="TexFormula1" title="-3/z+7/4z=5/z-25" alt="-3/z+7/4z=5/z-25" a
ycow [4]

Answer:

z = 1/4

Step-by-step explanation:

See attached image

4 0
2 years ago
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Solve This Using The Quadratic Formula: 3x^2+9x-6=0
aivan3 [116]
<h3>Therefore either  x = \frac{-3+\sqrt{17}}{2}    or,  x = \frac{-3-\sqrt{17}}{2}</h3>

Step-by-step explanation:

3x^2 +9x -6=0                                x = \frac{-b\pm\sqrt{b^2- 4ac} }{2a}

\Leftrightarrow x = \frac{-9\pm\sqrt{9^2- 4.3(-6)} }{2.3}                     here a = 3 ,b = 9 and c= -6

\Leftrightarrow x = \frac{-9\pm\sqrt{153} }{6}

\Leftrightarrow x = \frac{3(-3\pm\sqrt{17}) }{6}

\Leftrightarrow x = \frac{-3\pm\sqrt{17}}{2}

Therefore either  x = \frac{-3+\sqrt{17}}{2}    or,  x = \frac{-3-\sqrt{17}}{2}

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3 years ago
A regular polyhedron whose six faces are congruent squares
valentinak56 [21]

Answer:

True

Step-by-step explanation:

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