(3,-1)? i believe that's what it would be
2,3,7,8=
1)3*7=21
2)2*8+7=32
3)7*3+8=29
4)7*3+2=23
5)7*8 divided by 2=28
6)8*3=24
7)2*3*8=48
Hopes This Helps :)
it harden in pops because the helium in side
Answer:
This can be done in a total of 10 ways
Step-by-step explanation:
This is a selection problem.
What we are trying to do is to properly select 3 week long camps from the total 5. we are looking for the number of ways in which we can do this.
Now, since this is a selection problem, the proper mathematical term and approach to use is the COMBINATION
Mathematically, having r items to pick from a total n, the number of ways to do this is nCr ways
which is mathematically equivalent to;
n!/(n-r)!r!
now applying this to the problem at hand, what we have is 5C3
= 5!/(5-3)!3! = 5!/2!3! = (5 *4)/2 = 20/2 = 10 ways
Answer:
Equation: f(x)=x²-4x+3
Stretch factor: a=1
Step-by-step explanation:
Notice the x-intercepts are (1,0) and (3,0) which can help us determine the equation by setting their expressions equal to 0 and expanding:
(x-1)(x-3)=0
x²-4x+3=0
Therefore, the equation is f(x)=x²-4x+3 where the stretch factor is a=1
