Let x = number of 5 cent coins.
Then there are (x+2) 10 cent coins.
Let y = 20 cent coins.
Total coins: x+(x+2)+y = 30
2x+y=28
y = 28-2x (1)
Total value: 0.05x + 0.1(x+2) + 0.2y = 3.80
0.15x + 0.2y + 0.2 = 3.80
0.15x + 0.2y = 3.60 (2)
Substitute (1) into (2).
0.15x + 0.2(28-2x) = 3.60
-0.25x + 5.60 = 3.60
2.00 = 0.25x
8 = x
From (1), obtain y = 28 - 2(8) = 12
Answer: (x+2) = 8+2 = 10
Louise has 10 10-cent coins
Answer:
I'm pretty sure it's (0,1)
For this case we have two functions of the form y = f (x). We must find the quotient of the following functions:
So, we have by definition:
Answer:
with 3x + 5 different from zero, so that the function is defined
The answer is c
I got it right on edg 2020
Hey!
It says that it is the sum of 3 consecutive odd integers right?
So then we give these numbers some variables to work with like so...
x = 1st number
x + 2 = 2nd number
x + 4 = 3rd number
now set all of them equal to 207
x + x + 2 + x + 4 = 207
3x + 6 = 207
3x = 201
<u>x = 67</u><u /> <u>x + 2 = 69</u><u /> <u /><u /> <u>x + 4 = 71
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