Given that
z₁ = 15 (cos(90°) + i sin(90°))
z₂ = 3 (cos(10°) + i sin(80°))
we get the quotient z₁/z₂ by dividing the moduli and subtracting the arguments:
z₁/z₂ = 15/3 (cos(90° - 10°) + i sin(90° - 10°))
z₁/z₂ = 5 (cos(80°) + i sin(80°))
so that z₁ is scaled by a factor of 1/3 and is rotated 10° clockwise.
Answer: 3(x+2)
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The answer is 14 because 14×14=196
The answer for this question is b
