Answer:
Aceleracion = 4 m/s²
Step-by-step explanation:
Dados los siguientes datos;
Velocidad inicial = 10 m/s
Velocidad final = 70 m/s
Tiempo, t = 12 segundos
Para encontrar la aceleración;
Aceleración se puede definir como la tasa de cambio de la velocidad de un objeto con respecto al tiempo.
Matemáticamente, la aceleración viene dada por la fórmula;

Sustituyendo en la fórmula, tenemos;


Aceleracion = 4 m/s²
Answer:
I hate to do and take the points but so we just got to find the angles?
Answer: A
Step-by-step explanation:
Use pythagorean thm to solve for the hypotenuse. so
is 13.4
Answer:
v = 23
Step-by-step explanation:
Formatting the question gives;
a = mg - kv² / m
Make v subject of the formula as follows;
(i) Multiply both sides by m
ma = m²g - kv²
(ii) Collect like terms
kv² = m²g - ma
(iii) Divide through by k
v² = (m²g - ma) / k
(iv) Take the square root of both sides
v = √ [(m²g - ma) / k] --------------(ii)
From the question:
a = 2.8
m = 12
g = 9.8
k = 8/3
Substitute these values into equation (i) as follows;
v = √ [(12²(9.8) - 12(2.8)) / (8/3)]
v = √ [(1411.2 - 33.6) / (8/3)]
v = √ [1377.6 / (8/3)]
v = √ [1377.6 x (3/8)]
v = √ [1377.6 x 3 / 8)]
v = √ [516.6]
v = 22.73
v = 23 [to the nearest whole number]
Therefore v = 23 to the nearest whole number
Answer:
Step-by-step explanation:
1) ABCD is a trapezium. AB ║ CD
∠ADC + ∠DAB = 180° { Co interior angles}
110° + ∠DAB = 180
∠DAB = 180 -110
∠DAB = 70°
2) Sum of all angles of trapezium = 360°
∠A + ∠B + ∠DCB + ∠D = 360
70° + 50° + ∠DCB + 110° = 360
230 + ∠DCB = 360
∠DCB = 360 - 230
∠DCB = 130°
3) For finding the height, use Pythagorean theorem
height² + base² = hypotenuse²
height² + 6² = 10²
height² + 36 =100
height² = 100 - 36
height² = 64
height = √64
height = 8 m
4) a = AB = x m
b = 9 m
h = height = 8 m
Area of trapezium = 120 m²
= 120

x + 9 = 120/4
x + 9 = 30
x = 30 - 9
x = 21 m
AB = 21m