First, find the equation
y = F(x) = x +3
Then plug in 2 for x ( you could also go to 2 on the x-axis to find the Y)
F(2) = (2)+3
F(2) = 5
39 whatevers is how far it flys in a hour
So basically 5x+5/(x)(x)-2. the integers involving vertical movement I think would be 5 and -2
Simply put 10 in all of the boxes. There are 5 boxes. And all those boxes equal 50, right? So for every box, there's 10 students. 10 multiplied by 5 is equal to 50.
