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lana [24]
2 years ago
15

Which inequality represents “a number is at most two”?

Mathematics
2 answers:
Montano1993 [528]2 years ago
7 0
The answer is C.) x is less than or equal to 2
wolverine [178]2 years ago
4 0

Answer:

C

Step-by-step explanation:

The line under < shows that the number can equal two and because it is facing the two a number cannot be greater.

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Please help me on this! will give you brainliest, ty:,
Artist 52 [7]

Answer: 4^9

Step-by-step explanation:

4^-7 is just 1/4^7 so this is equal to 4^2 divided by 1/4^7. Dividing by a fraction is the same thing as multiplying by its reciprocal (just flip the fraction). So this whole equation is equal to 4^2 multiplied by 4^7. And when you multiply two exponents with the same base, the exponents are just added. So, your answer should be 4^9. Hope this helps! :)

3 0
2 years ago
HELP I NEED THIS DONE FAST
Rudiy27

Answer:

<h3>80.1 x 10 <em>7</em></h3>

Step-by-step explanation:

5 0
3 years ago
You can read 52 pages per hour.
lidiya [134]

Answer:

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2 years ago
Read 2 more answers
A woman takes 121212 equal-sized steps. She walks a total of 10 \text { yards}10 yards10, start text, space, y, a, r, d, s, end
kramer

Answer:

30 inches

Step-by-step explanation:

She takes 12 equal sized steps and they all add up to 10 yards.

The length of each step (in yards) is:

10 / 12 = 5/6 yards

The question requires the answer in inches, therefore, we must convert this to inches:

1 yard = 36 inches

5/6 yards = 5/6 * 36 = 30 inches

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5 0
2 years ago
Water flows at 12 m/s in a horizontal pipe with a pressure of 3.0 104 n/m2. if the pipe widens to twice its original radius, wh
Alexxx [7]
Total pressure is constant and PT = P = 1/2*ρ*v^2 So p1 + 1/2*ρ*v1^2 = p2 + 1/2*ρ*v2^2 and from continuity we have ρ*A1*v1 = ρ*A2*v2 So v2 = v1*A1/A2 since r2 = 2r1 then A2 = 4A1 so v2 = v1/4 Now from above p2 = p1 + 1/2*ρ*v1^2 - 1/2*ρ*v2^2 = p1 + 1/2*ρ*v1^2 - 1/2*ρ*v1^2/4^2 So p2 = 3.0x10^4Pa + 1/2*1000kg/m^3*(12m/s)^2 - 1/2*1000kg/m^3*12^2/16 = 9.75x10^4Pa = 9.8x10^4Pa
7 0
3 years ago
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