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sammy [17]
2 years ago
11

Please help with this problem

Mathematics
1 answer:
Paraphin [41]2 years ago
7 0

Answer:

Step-by-step explanation:

See attachment.

The change from x to (x-4) moved the function to the right by 4.  The - 5 moved it down by 5 (as measured from the crossover/inflection point.

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\boxed{\sf x=\cfrac{1\pm \sqrt{-7} }{2}}

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\sf x^2-x+2=0

<u>Use quadratic formula:</u>

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___________________________

\sf x_1,_2=\cfrac{-\left(-1\right)\pm \sqrt{\left(-1\right)^2-4\times \:1\times \:2}}{2\times \:1}

  • \sf \sqrt{\left(-1\right)^2-4\times \:1\times \:2}
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_________________

\sf x_1,_2\cfrac{-\left(-1\right)\pm \sqrt{-7}}{2\times \:1}

  • \sf -(-1)=1
  • 2\times 1=2

\sf x_1,_2=\cfrac{1\pm \sqrt{-7} }{2}

_______________________________________

<u>Learn more: brainly.com/question/22286698</u>

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