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JulijaS [17]
3 years ago
9

Whats the solution.?

Mathematics
2 answers:
Margaret [11]3 years ago
6 0
x-4=-1/5x+2
Add 4 to both sides
x=-1/5x+6
Add 1/5x to both sides
6/5x=6
Multiply each side by 6/5
X=7.2
Viefleur [7K]3 years ago
4 0

Answer:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    y-(x-4)=0  

STEP

1

:

Equation of a Straight Line

1.1     Solve   y-x+4  = 0

Tiger recognizes that we have here an equation of a straight line. Such an equation is usually written y=mx+b ("y=mx+c" in the UK).

"y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis.

 

In this formula :

y tells us how far up the line goes

x tells us how far along

m is the Slope or Gradient i.e. how steep the line is

b is the Y-intercept i.e. where the line crosses the Y axis

The X and Y intercepts and the Slope are called the line properties. We shall now graph the line  y-x+4  = 0 and calculate its properties

Step-by-step explanation:

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Answer:

Equation of circle in standard form with centre (0, – 10) and radius 6. \mathbf{x^2+(y+10)^2=36}

Step-by-step explanation:

We need to write equation of circle in standard form with centre (0, – 10) and radius 6.

The equation of circle is: (x-h)^2+(y-k)^2=r^2

where (h,k) is centre of circle and r is radius

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Putting values and finding equation:

(x-h)^2+(y-k)^2=r^2\\(x-0)^2+(y-(-10))^2=(6)^2\\x^2+(y+10)^2=36

So, equation of circle in standard form with centre (0, – 10) and radius 6. \mathbf{x^2+(y+10)^2=36}

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Line A is perpendicular to line B. The slope of line A is -1/9 what is the slope of line b?
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