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2 years ago

APES + WILL GIVE BRAINLIST WHEN CAN + 30 POINTS PER PERSON I BELIEVE. PLEASE HELP

Advanced Placement (AP)

1 answer:

Misha Larkins [42]2 years ago

5 0

Answer:

the Mississippi watersheds effetces mat affet watersheds diepicted in pthe picture of china

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Roger can use his existing resources to produce the following combinations of goods. Based on this information, which of the fol

lora16 [44]

The answer choice which is true that Roger enjoys an absolute advantage in the production of skateboards

<h3>What is absolute advantage?</h3>

Absolute advantage can be defined as the ability of a party to produce a good or service more efficiently than its competitors.

In conclusion, Roger enjoys an absolute advantage in the production of skateboards

Learn more about absolute advantage:

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1 year ago

Joseph belonged to the line of King David. True False this is a bible question

Vikki [24]

True. Joseph is a descendant of King David. (pretty sure)

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3 years ago

Hello, I need help with a calculus FRQ. My teacher has given a hint that this last part has to do with the intermediate value th

lesya [120]

Answer:

Yes, at a time t such that (√2)/2 ≤ t ≤ 2.

Explanation:

To answer the question

Therefore, where the domain of the function is the set of all real numbers x for which f(x) is a real number we have

For Chloe's velocity

$C(t) = t\times e^{4-t^2} \ for \ 0\leq t\leq 2$

Finding the boundaries of the function gives;

$0\times e^{4-0^2} = 0$ and $2\times e^{4-2^2} = 2$

At t = 1, we have $1\times e^{4-1^2} = e^{3} = 20.086$

We find the maximum point as follows;

$\frac{\mathrm{d} \left (t\times e^{4-t^2} \right )}{\mathrm{d} x}=0$

From which we have;

$\frac{\mathrm{} e^{4-t^2} - t\times e^{4-t^2} \times2\times t }{(e^{4-t^2} )^2}=0$

$e^{4-t^2} - t\times e^{4-t^2} \times2\times t }=0$

$e^{4-t^2}(1 - t\times2\times t })=0\\e^{4-t^2}(1 - 2\times t^2 })=0\\$

$e^{4-t^2}=0$ or $(1 - 2\times t^2 })=0$

∴ 1 = 2·t² and from which t = (√2)/2

Hence the function C(x) is decreasing from t = (√2)/2 to t = 2

For Brandon

For 0 ≤ t ≤ 1, 1 ≤ B(t) ≤8 and for 1 < t ≤ 2, 8 < B(t) ≤ 1.5

1 ≤ f(x) ≤ 1.5

Given that the function B(t) is differentiable, therefore, continuous, there exists a point at which the function C(t) and B(t) intersects given that;

For 0 ≤ t ≤ (√2)/2, 0 ≤ C(t) ≤ 23.416 for (√2)/2 < t ≤ 2, 23.416 > C(t) ≥ 2

and for 0 ≤ t ≤ 0 1 ≤ B(t) ≤ 8 and for 1 < t ≤ 2, 8 > B(t) ≥ 1.5

Therefore, the curves intersect at in between (√2)/2 ≤ t ≤ 2.

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3 years ago

Garbanzo bean ? garbanzo bean ?

zzz [600]

Answer:

Papaya??? Oooh I know I know beannnnnnnn!!!

Explanation:

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3 years ago

Schizophrenia occurs in about _____ percent of the population and is slightly more prevalent in _____

makkiz [27]

<span>Schizophrenia occurs in about 1.1 percent of the population and is slightly more prevalent in men. This disease tends to manifest in a patient's mid to late twenties, so estimates are only for those over the age of 18.</span>

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3 years ago

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