I’m pretty sure that the one you marked is correct
The percent increase in the iron was 50%. 1.2/2 = .6 1.2 + .6 = 1.8
The chances that NEITHER of these two selected people were born after the year 2000 is 0.36
<h3>How to determine the probability?</h3>
The given parameters are:
Year = 2000
Proportion of people born after 2000, p = 40%
Sample size = 2
The chances that NEITHER of these two selected people were born after the year 2000 is calculated as:
P = (1- p)^2
Substitute the known values in the above equation
P = (1 - 40%)^2
Evaluate the exponent
P = 0.36
Hence, the chances that NEITHER of these two selected people were born after the year 2000 is 0.36
Read more about probability at
brainly.com/question/25870256
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Answer:
b
Step-by-step explanation:
Well it is true if the problem is the right with the right answer. If not you have a false eqaution.
