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2 years ago

The quality control manager at a battery factory picks three batteries at random each day from the production line.

Mathematics

1 answer:

azamat2 years ago

6 0

Answer : 0.001

Step - by - step explanation :

If 90% of the batteries are produced perfectly which equals to . . . 90 / 100. That therefore means that 10 / 100 of the batteries are imperfect.

So it's 0.001 !

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There are 3 types of sweets in a jar.

KengaRu [80]

Answer:

$\frac{2}{3}$

Step-by-step explanation:

Given:

Number of eclairs = 3

Number of humbugs = $2x + 6=2(x+3)$

Number of mints = $x$

Therefore, total number of sweets in the jar is,

$S=3+2x+6+x=3x+9=3(x+3)$

Now, probability of selecting a sweet to be humbug is given as:

$P(humbug)=\frac{\textrm{number of humbugs}}{\textrm{number of sweets}}\\P(humbug)=\frac{2(x+3)}{3(x+3)}=\frac{2}{3}$

Therefore, the probability that it is a humbug is $\frac{2}{3}$ .

7 0

2 years ago

Simplify the expression.<br> I NEED HELP PLEASE!!!

tatiyna

Answer:

-27/64p^3

Tell me if you want a step by step. :)

7 0

1 year ago

It's candy time! Suppose 5 friends go out candy collecting. Starting out, Ms. Gleason gave each of them 12 pieces of candy. Then

sdas [7]

Answer:

6 hours

Step-by-step explanation:

First, since they all collected 510, you divide 510 by 5, to figure out how much each person got.

You then know that each of them got 102 candies, so now, you subtract 12 from from 102, since the teacher gave them that much in the beginning.

You're left with 90, so last step is to divide 90 by 15, since they collect 15 every hour, which you get left with 6. Meaning they collected candies for 6 hours

8 0

1 year ago

Read 2 more answers

Gus wrote the following riddle: I am a number between 30 and 60. My ones digit is three less than my tens digit. I am a prime nu

Neporo4naja [7]

Answer: 41

Step-by-step explanation:

6 0

2 years ago

If outliers are discarded, then the retirement savings by residents of Econistan is normally distributed with a mean of $100,000

zavuch27 [327]

Answer:

$P(X>117000)=P(\frac{X-\mu}{\sigma}>\frac{117000-\mu}{\sigma})=P(Z>\frac{117000-100000}{20000})=P(z>0.85)$

And we can find this probability using the complement rule and the normal standard table or excel:

$P(z>0.85)=1-P(z$

The firgure attached illustrate the problem

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the retirement savings of a population, and for this case we know the distribution for X is given by:

$X \sim N(100000,20000)$

Where $\mu=100000$ and $\sigma=20000$

We are interested on this probability

$P(X>117000)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>117000)=P(\frac{X-\mu}{\sigma}>\frac{117000-\mu}{\sigma})=P(Z>\frac{117000-100000}{20000})=P(z>0.85)$

And we can find this probability using the complement rule and the normal standard table or excel:

$P(z>0.85)=1-P(z$

The firgure attached illustrate the problem

7 0

2 years ago