Ask question

Ask question

All categories

3 years ago

6

You want to purchase a pair of shoes for at least $150. You have $55 so far. You earn $10.00 per hour at your job write an inequ

ality that represents the minimum number of hours H that you need to work

1 answer:

VikaD [51]3 years ago

7 0

55+10.00x ≥ 150 x ≥ 9.5 hours I hope that helps

You might be interested in

Please answer quickly<br><br><br><br><br> 40 points

Elis [28]

Answer:

2/5 hour is closest to 0 1/2 hours, 5/8 hour is closest to 1/2 hour. Therefore, the best estimate for the total time Maria spent with her sister is close to 1 hour

Step-by-step explanation:

We can represent the time Maria spends playing the game as 0.4, since 2/5 as a fraction is 0.4. This is closer to 1/2, which is 0.5 then it is to 0, because 4 is closer to 5 then 0. Then, we can represent the time Maria reads the book as 0.625, which is closer to 1/2 then it is to 1. Now we can add the estimated times. $1/2+1/2=1$ hour

8 0

2 years ago

What is the price of a $35 taxi ride plus 15% tip

Sveta_85 [38]

If there only one person then the total would be $40.25

7 0

2 years ago

Owen has $7000 in a savings account and $3000 invested in the stock market, he owns a car worth $12,000, he has $13,000 left to

Vinil7 [7]

Answer=$8400
Add all the assets 7,000+3,000+12,000=$22,000
Add debts 13,000+600=$13,600
Assets - Debts
$22,000-13,600=$8,400

3 0

3 years ago

Read 2 more answers

List 3 values that would make this inequality true 43 < y -30

prohojiy [21]

43 < y - 30
add 30 to both sides
73 < y

y can be anything that is greater than 73
so it could be...
101, 74, 90, 75, 980767, 5674, etc.

Hope this helps!

4 0

3 years ago

What is the completely factored form of d4 -8d2 + 16

irinina [24]

According to Vieta's Formulas, if $x_1,x_2$ are solutions of a given quadratic equation:

$ax^2+bx+c=0$

Then:

$a(x-x_1)(x-x_2)$ is the completely factored form of $ax^2+bx+c$ .

If choose $x=d^2$ , then:

$\displaystyle x^2-8x+16=0\\\\x_{1,2}= \frac{8\pm \sqrt{64-64} }{2}=4$

So, according to Vieta's formula, we can get:

$x^2-8x+16=(x-4)(x-4)= (x-4)^2$

But $x=d^2$ :

$d^4-8d^2+16=(d^2-4)^2=[(d+2)(d-2)]^2=(d+2)^2(d-2)^2$

8 0

3 years ago