Cat weight = 14,000 / 10^3
= 14,000 / 10000
= 14 pounds
44

-3x + 2 > 14.
-2 -2 -2
42

-3x > 12
-------------------------------------
-3 -3 -3 (dividing with inequalities by a negative flips the inequality symbol)
-14

x < -4
For this exercise it is important to know that, in Dilations:
1. When the scale factor is greater than 1, the Image (the figure obtained after the transformation) is an enlargement.
2. When the scale factor is greater than 0 but less than 1, the Image is a reduction:
![0You know that the coordinates of the vertices of the polygon ABCD are:[tex]\begin{gathered} A(2,4) \\ B(-4,-8) \\ C(0,4) \\ D(12,-2) \end{gathered}](https://tex.z-dn.net/?f=0You%20know%20that%20the%20coordinates%20of%20the%20vertices%20of%20the%20polygon%20ABCD%20are%3A%5Btex%5D%5Cbegin%7Bgathered%7D%20A%282%2C4%29%20%5C%5C%20B%28-4%2C-8%29%20%5C%5C%20C%280%2C4%29%20%5C%5C%20D%2812%2C-2%29%20%5Cend%7Bgathered%7D)
And the scale factor is:

Since:

It is a reduction.
You can identify that the rule of this transformation is:
9514 1404 393
Answer:
- New York style: $14
- Chocolate Marble: $16
Step-by-step explanation:
We can let n and c represent the costs of the New York style and the chocolate marble cheesecakes, respectively. Then the two sales are ...
11n +7c = 266 . . . . . . . Rob's sale
4n +14c = 280 . . . . . . Amy's sale
The ratio of coefficients of c is a "nice" number (2), so we can eliminate the c variable easily to solve this. Dividing the second equation by 2 and subtracting it from the first gives ...
(11n +7c) -(1/2)(4n +14c) = (266) -(1/2)(280)
9n = 126 . . . . . . simplify
n = 14 . . . . . . . . divide by 9
Filling this into the first equation, we have ...
11(14) +7c = 266
7c = 112 . . . . . . . . subtract 154
c = 16 . . . . . . . divide by 7
One New York style cheesecake costs $14; one chocolate marble cheesecake costs $16.