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Yuri [45]
2 years ago
11

Plssssss helppppppppppp​

Mathematics
2 answers:
lubasha [3.4K]2 years ago
5 0
I believe the answer is A
PilotLPTM [1.2K]2 years ago
4 0

Answer:

it is a

Step-by-step explanation:

if there are 12 students in a class that is your detonator in toatal and 8 of the 12 have pets it is 8/12

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Find the slope of the line.<br> 1.<br> (5, 3)<br> (-5, 1)
Blizzard [7]

Answer:

1/5

Step-by-step explanation:

y1-y2/x1-y2 = (3-1)/5-(-5)

8 0
3 years ago
To fit in an existing frame, the length, x, of a piece of glass must be longer than 12 cm but not longer than 12.2 cm. Which ine
anastassius [24]
Inequality that represents the lengths of the glass:
12 cm <  x  ≤ 12.2 cm

7 0
3 years ago
Read 2 more answers
b) How many ways can you deal cards (from a deck of 52) to 4 people when each player gets 7 cards. 2 hidden and 5 visible. Assum
Mariana [72]

Answer:

{52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

Step-by-step explanation:

The dealing of the cards can be seen in the following way:

We first have to choose which 7 cards are going to be dealt to the 1st player. So we have to pick 7 cards out of the 52 available cards. This can be done in {52 \choose 7} ways. Now that we have chosen which 7 cards are going to be dealt to the 1st player, we have to choose which 2 of them are going to be the hidden ones. So we have to pick 2 cards out of the 7 cards to be the hidden ones. This can be done in {7 \choose 2} ways. At this point we now know which cards are being dealt to the 1st player, and which ones are hidden for him. Then we have to choose which 7 cards to deal to the 2nd player, out of the remaining ones. So we have to pick 7 out of 52-7=45. (since 7 have been already dealt to the 1st player). This can be done in {45 \choose 7}. Then again, we have to pick which 2 are going to be the hidden cards for this 2nd player. So we have to pick 2 out of the 7. This can be done in {7 \choose 2} ways. Then we continue with the 3rd player. We have to choose 7 cards out of the remaining ones, which at this point are 52-7-7=38. This can be done in {38 \choose 7}. And again, we have to choose which ones are the hidden ones, which can be chosen in {7 \choose 2} ways. Finally, for the last player, we choose 7 out of the remaining cards, which are 52-7-7-7=31. This can be done in {31 \choose 7} ways. And choosing which ones are the hidden ones for this player can be done in {7 \choose 2} ways. At the end, we should multiply all our available choices on each step, to get the total choices or total ways to deal the cards to our 4 players (since dealing the cards is a process of several steps with many choices on each step).

{52 \choose 7}{7 \choose 2}{45 \choose 7}{7 \choose 2}{38 \choose 7}{7 \choose 2}{31 \choose 7}{7 \choose 2}={52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

7 0
3 years ago
Given: 3x+7+2(4x+1) = 3(x-1) -4 prove: x=-2
denis23 [38]

Answer:

x = -2, proven below.

Step-by-step explanation:

3x + 7 + 2(4x+1) = 3(x-1) - 4

3x + 7 + 8x + 2 = 3x - 3 - 4

9 + 11x = 3x - 7

16 + 11x = 3x

16 = - 8x

-2 = x

7 0
3 years ago
Find the real solution(s) of the following equation.
nydimaria [60]

Answer:

a=9

Step-by-step explanation:

a^3 = 729

Taking the cube root of each side

a^3 ^(1/3) = 729^ (1/3)

a = 9

4 0
2 years ago
Read 2 more answers
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