Answer: The answer is ![\sqrt[4]{8}.](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B8%7D.)
Step-by-step explanation: Given expression is

We are to find the radical form of the above expression, i.e., we need to write the expression in a form that involves n-th roots of a particular number.
For example, consider the below identity.
![a^\frac{c}{d}=\sqrt[d]{a^c}.](https://tex.z-dn.net/?f=a%5E%5Cfrac%7Bc%7D%7Bd%7D%3D%5Csqrt%5Bd%5D%7Ba%5Ec%7D.)
Using this result, we can solve the given problem as follows
![2^\frac{3}{4}=\sqrt[4]{2^3}=\sqrt[4]{8}.](https://tex.z-dn.net/?f=2%5E%5Cfrac%7B3%7D%7B4%7D%3D%5Csqrt%5B4%5D%7B2%5E3%7D%3D%5Csqrt%5B4%5D%7B8%7D.)
Thus, the required radical form is ![\sqrt[4]{8}.](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B8%7D.)
Oooo this a little bit to hard for me I’m sorry
Answer:
Step-by-step explanation:
Answer
2600
Explanation
Based on the given conditions, formulate: 2000+30,000x2%
Calculate the product or quotient:2000+600
Calculate the sum or difference:2600
get the result:2600
Answer: 2600
Hope this helps from Armax
Answer: Letter C: 11
Step-by-step explanation:5 times 2.2=11
Differentiate using the chain rule:
d/du [ln(u)] d/dx[2x^3+3x]
derivative of ln(u) = 1/u
1/u d/dx[2x^3+3x]
1/2x^3+3x d/dx[2x^3+3x]
Differentiate
(6x^2+3) 1/2x^3+3x
Simplify
Dy/dx = 3(2x^2+1) / x(2x^2 +3)