I: 12x-5y=0
II:(x+12)^2+(y-5)^2=169
with I:
12x=5y
x=(5/12)y
-> substitute x in II:
((5/12)y+12)^2+(y-5)^2=169
(25/144)y^2+10y+144+y^2-10y+25=169
(25/144)y^2+y^2+10y-10y+144+25=169
(25/144)y^2+y^2+144+25=169
(25/144)y^2+y^2+169=169
(25/144)y^2+y^2=0
y^2=0
y=0
insert into I:
12x=0
x=0
-> only intersection is at (0,0) = option B
C because if you look at the intercept it’s a y and the y inception is equivalent to 4 so y=4x-14
Cosine is
which applies to a right triangle. I hope that helps you.
Answer:
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I can't believe how much I love the opportunity and I have a strong doubt that she is it possible for you to know if you get the chance to read it and it is
let your keyboard type for you
Let the number x.
Then the number divided by 2 gives
Subtract 3.8 from the quotient gives
Hence,
x = 21.6
