40=4x then 45=4.5x solving "x" as 1 in per 10 pounds.
Answer:
The polynomial 3x² + x - 6x + 3 is a prime polynomial
How to determine the prime polynomial?
For a polynomial to be prime, it means that the polynomial cannot be divided into factors
From the list of options, the polynomial (D) is prime, and the proof is as follows:
We have:
3x² + x - 6x + 3
From the graph of the polynomial (see attachment), we can see that the function does not cross the x-axis.
Hence, the polynomial 3x² + x - 6x + 3 is a prime polynomial
Read more about prime polynomial at:
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Answer:
The answer is 35.
Step-by-step explanation:
Prime numbers that are less than 50 are --> 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47
The largest prime number in here that is less than 50 is 47, right?
Lastly, the smallest composite number which is greater than 10 is what? It is 12, okay?
So, 47 - 12 = 35
5.
To find this, you can do the is over of technique.
The is over of technique is as says - is over of and percent over one hundred.
If you use this technique, your equation should look like this:
x/50 = 10/100
Cross multiply 10 and 50 and divide by 100 to get the answer of 5.
Hope this helps!
Answer:
(a) The data set is a function, since for each input value {3,4,6,11} there is a single output value {5,7,11,21}
(B) A function is a mathematical relationship that associates one or more inputs with a single output value. So that the data set is not a function, there should be - for one or more values of the input - more than one output.
for example, if for the input value {3} there were two outputs {5, -5} then, the data set would not be a function.
The frelation
is not a function because:
When x = 1, y = +1 and y = -1.
(c) The set of data provided can be represented by the equation of a line of the form y = mx + b
The slope is:


m = 2

b = 5 - 2*3
b = -1
Then, the function is:
y = 2x-1
You can substitute any of the points shown in the equation and check that equality is satisfied, for example:
(11 , 21)
y = 2 (11) -1
y = 22-1
y = 21. The equation is satisfied. The same goes for the rest of the values.