Hello,
Assume Ax+By+Cz+D=0 the plane 's equation.
p=(0,0,0)==>A*0+B*0+C*0+D=0==>D=0
q=(0,1,0)==>A*0+B*1+C*0+0=0==>B=0
r=(1,2,3)==>A*1+0*2+C*3+0=0==>A=-3C
Let C=1==>A=-3
An equation of the plane is -3x+z=0
Step-by-step explanation:
Circumference of a circle is 2piR
Here R is 3 cm
So C=2pi(3)
C=6pi cm
Answer:
83343249
Step-by-step explanation:
A(-3, -1); B(2, -1), C(2, 3)
You can read the length of AB and BC.
|AB| = 5
|BC| = 4
Use the Pythagorean theorem:

The perimeter:
