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atroni [7]
3 years ago
13

Please help if you know geometry I will mark brainliest

Mathematics
1 answer:
algol [13]3 years ago
7 0

Answer:

A

Step-by-step explanation:

A clock in a hour makes a rotation of 360 degrees. So this emans each minute will make a rotation of 6 degrees. 12:12 to 12:50 is 38 degrees So

38 \times 6 = 228

A

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F(-2)=15, F(1)=9 can someone help me please
pogonyaev

Answer:

y= -2x +11

Step-by-step explanation:

the 2 points: (-2,15) and (1,9)

find the slope: 6/ -3 = -2

find y-intercept: 9 = -2 + b       b=11

4 0
3 years ago
What is the value of x in the proportion (x - 1)/5 = (4x + 2)/35?
nirvana33 [79]

Answer:

x=3

Step-by-step explanation:

1. cross multiply to get

5(4x+2)= 35(x-1)

2. distribute

20x+10=35x-35

3. combine like terms

45=15x

4. divide :)

3=x

6 0
3 years ago
Read 2 more answers
Sarah is building a model of the school. the scale of her model to the actual school is 1 to 10. Her model is 380 in tall. How t
Leni [432]
So for this I would set up a ratio. 1/10=x/380 then you cross multiply so 1x380=10x. Then solve the equation so 380/10=x and you get 38in. Hope my explanation helped!
4 0
4 years ago
How do I answer this problem 24/5+_+8/7=9​
juin [17]
Uhm so that is the photo

5 0
3 years ago
A market research firm supplies manufacturers with estimates of the retail sales of their products from samples of retail stores
EastWind [94]

Answer:

(52-49) -4.300= -1.300

(52-49) +4.300= 7.300

And the 95% confidence would be :

-1.300 \leq \mu_1 -\mu_2 \leq 7.300

Step-by-step explanation:

We have the following info given from the problem

\bar X_1 = 52 sample mean for this year

s_1= 13 sample deviation for this year

n_1 = 75 random sample selected for this year

\bar X_2 = 49 sample mean for last year

s_2= 11 sample deviation for last year

n_1 = 53 random sample selected for last year

And we want to construct a 95% confidence interval estimate of the difference μ1−μ2, where μ1 is the mean of this year's sales and μ2 is the mean of last year's sales

For this case the formula that we need to use is:

(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}

The degrees of freedom are given by:

df= n_1 +n_2 -2 = 75+53-2= 126

The confidence level is 0.95 and the significance would be \alpha=0.05 and \alpha/2 =0.025 so then the critical value for this case is :

t_{\alpha/2}= 1.979

The margin of error would be:

ME = 1.979 \sqrt{\frac{13^2}{75} +\frac{11^2}{49}}= 4.300

And the confidence interval would be given by:

(52-49) -4.300= -1.300

(52-49) +4.300= 7.300

And the 95% confidence would be :

-1.300 \leq \mu_1 -\mu_2 \leq 7.300

6 0
4 years ago
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