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Alchen [17]
3 years ago
6

This is the next question. Solve: 8( 4 - 2^{6} ÷ 4)

Mathematics
2 answers:
Ronch [10]3 years ago
4 0
8(4-2^6/4)
8(4-64/4)
8(4-16)
8(-11)
-88
Tatiana [17]3 years ago
3 0

Hey there!

8( 4 - 2^{6} ÷ 4)

= 8( 4 - 2^6 ÷ 4)

2^6

= 2 * 2 * 2 * 2 * 2 * 2

= 4 * 4 * 4

= 16 * 4

= 64

= 8(4 - 64 ÷ 4)

= 8(4) + 8(-16)

= 32 - 128

= -96

Therefore, your answer is: -96

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

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The length of a rectangle is two thirds its width. the area is 12 square meters. find its width. round your answer to two decima
ziro4ka [17]
L = ( \frac{2}{3} )w
a = 12 
Length times width = area 
L · w = a
( \frac{2}{3} )w · w = 12
( \frac{2}{3} ) w^{2} = 12
Divide both sides by \frac{2}{3} or mulitply both sides by \frac{3}{2} (either one is fine)
( \frac{2}{3} ) ÷ ( \frac{2}{3} ) w^{2} = 12 ÷ ( \frac{2}{3} )
or
( \frac{3}{2} ) ( \frac{2}{3} ) w^{2} = 12 ( \frac{3}{2} )
w^{2} = 18
Square root both sides to get rid of the squared on the w
\sqrt{w^{2} } = \sqrt{18}
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The sum of two numbers is 41 . The smaller number is 11 less than the larger number . What are the numbers ?
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3 years ago
One side of a rectangle is 6 yd longer than three times another side. The area of the rectangle is 72 yd2. Find the length of th
TiliK225 [7]

Answer:

18 yds

Step-by-step explanation:

Let the length and width be L and W respectively.

Then L· W = area = 72 yd², so that L = (72 yd²) / W.

But also L = 3W + 6 yd.  Subbing this into  L· W = area = 72 yd², we get:

(3W + 6) · W = 72, or

3W² + 6W - 72 = 0.  Since all  four terms are evenly divisible by 3, we get:

W² + 2W - 24 = 0, which factors as follows:

(W + 6)(W - 4) = 0.  Then W + 6 = 0, or W = -6 (makes no sense for a length), and W - 4 = 0 yields W = 4 yds.

If the shorter side is of length 4 yds, then the longer side is of length

L = 3(4 yds) + 6 yds = 18 yds

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