Question

the hypotenuse of a right triangle is 5 centimeters longer than one leg and 10 centimeter longer than the other leg. what are the dimensions of the triangle?​

Answer 1

smaller leg be x

• other leg=x+5
• Hypotenuse=x+10

Using Pythagorean theorem

$\\ \sf\longmapsto x^2+(x+5)^2=(x+10)^2$

$\\ \sf\longmapsto x^2+x^2+10x+25=x^2+20x+100$

$\\ \sf\longmapsto x^2-10x-75=0$

• On solving we get x=15
• x+5=20
• x+10=25