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3 years ago

What does: 8w+22=34 equal?

Mathematics

2 answers:

navik [9.2K]3 years ago

6 0

Answer:

3/2

HOPE I HELPEDD

valina [46]3 years ago

4 0

Answer:

w= 1 1/2

I dont know if thats the question youre asking, if its not tell me.

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Need a little bit of help

klemol [59]

Answer:

Step-by-step explanation:

5 0

4 years ago

Help me out please. For 20 points.

Nata [24]

Answer:

7 1/3

Step-by-step explanation:

1 2/3 - ( -5 2/3)

Subtracting a negative is like adding

1 2/3 + 5 2/3

6 4/3

Simplify the fraction

6 3/3 + 1/3

7 1/3

4 0

3 years ago

Read 2 more answers

What is the solution set of the equation |2x+3|=7 in the set of rational numbers?

valina [46]

Answer:

Step-by-step explanation:

-10=-5*2; 4=2*2

l-10+3l= 7; l4+3l=7

8 0

3 years ago

Read 2 more answers

Factor the expression. Use the fundamental identities to simplify, if necessary.

Rasek [7]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identity

sin²x + cos²x = 1 ⇒ sin²x = 1 - cos²x

Given

sin²x + 7cosx + 17

=1 - cos²x + 7cosx + 17

= - cos²x + 7cosx + 18 ← factor out - 1 from each term

= - (cos²x - 7cosx - 18)

Consider the factors of the constant term (- 18) which sum to give the coefficient of the cosx term (- 7)

The factors are - 9 and + 2, thus

= - (cosx - 9)(cosx + 2) ← in factored form

3 0

3 years ago

A machine has four components, A, B, C, and D, set up in such a manner that all four parts must work for the machine to work pro

olchik [2.2K]

Answer:

0.756

Step-by-step explanation:

It is given that a machine has four components, A, B, C, and D.

$P(A)=P(B)=0.93, P(C)=0.95,P(D)=0.92$

If these components set up in such a manner that all four parts must work for the machine to work properly.

We need to find the probability that the machine works properly. It means we have to find the value of $P(A\cap B\cap C\cap D)$ .

If two events X and Y are independent, then

$P(X\cap Y)=P(X)\times P(Y)$

Assume the probability of one part working does not depend on the functionality of any of the other parts.

$P(A\cap B\cap C\cap D)=P(A)\times P(B)\times P(C)\times P(D)$

Substitute the given values.

$P(A\cap B\cap C\cap D)=0.93\times 0.93\times 0.95\times 0.92$

$P(A\cap B\cap C\cap D)=0.7559226$

$P(A\cap B\cap C\cap D)\approx 0.756$

Therefore, the probability that the machine works properly is 0.756.

7 0

3 years ago