W+(-4)=37 what is the w
2 answers:
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Answer:
3x - 4y= -17 or slope intercept form is y=
Step-by-step explanation:
Use the Ax+By=C equation
The change in the water vapors is modeled by the polynomial function c(x). In order to find the x-intercepts of a polynomial we set it equal to zero and solve for the values of x. The resulting values of x are the x-intercepts of the polynomial.
Once we have the x-intercepts we know the points where the graph crosses the x-axes. From the degree of the polynomial we can visualize the end behavior of the graph and using the values of maxima and minima a rough sketch can be plotted.
Let the polynomial function be c(x) = x ² -7x + 10
To find the x-intercepts we set the polynomial equal to zero and solve for x as shown below:
x ² -7x + 10 = 0
Factorizing the middle term, we get:
x ² - 2x - 5x + 10 = 0
x(x - 2) - 5(x - 2) =0
(x - 2)(x - 5)=0
x - 2 = 0 ⇒ x=2
x - 5 = 0 ⇒ x=5
Thus the x-intercept of our polynomial are 2 and 5. Since the polynomial is of degree 2 and has positive leading coefficient, its shape will be a parabola opening in upward direction. The graph will have a minimum point but no maximum if the domain is not specified. The minimum points occurs at the midpoint of the two x-intercepts. So the minimum point will occur at x=3.5. Using x=3.5 the value of the minimum point can be found. Using all this data a rough sketch of the polynomial can be constructed. The figure attached below shows the graph of our polynomial.
Answer:
The coordinates of HF are (1, 4)
Step-by-step explanation:
The parameters of the line are;
The coordinate of the end points are H = (-11, 7), and J = (5, 3)
The ratio by which the point F divides the line = 3:1
The segments in the line are HF, and FJ
Therefore;
The fraction of the length of HJ that is represented by HF = 3/(3 + 1) × HJ = 3/4 × HJ
HF = 3/4 × HJ
Which gives the coordinates of the point F as follows;
Coordinate of F = (-11 +(5 - (-11))×3/4, 7 + (3 - 7)×3/4) = (1, 4)
The coordinates of F are (1, 4)
We check the length of HF, from the equation for the length to of a line to get;
Similarly, we check the length of HJ, to get;
The length of HF = 3·√(17)
The length of HJ = 4·√(17)
Therefore, from HF = 3/4× HJ, we have;
HF = 3/4 × 4·√(17) = 3·√(17)
Therefore, the coordinates of HF are (1, 4)