Answer:
There must have two white genes to become white.
Explanation:
In order to a mouse to have white fur, both of their genes must be white. In the punnet square, you have a Black (BB) and a white (bb). If they have offspring, all of them have one black (Dominant) and one white (recessive). The black gene overpowers the white gene, so they come out black.
Options for the question are not given. They are as follows :
A. Mate them and see what color the offspring are—that will be the dominant color
B. Mate them and see what color the offspring are—the other will be the dominant color
C. Mate them, and then mate their offspring to see what color the next generation is
D. Mate them together, and then mate their offspring to see what color the next generation is—the other color will be the dominant color
Answer:
A. Mate them and see what color the offspring are—that will be the dominant color
Explanation:
Out of the two colors, one will be recessive and one will be dominant. Recessive color will be homozygous since it is only expressed in homozygous condition. It is also given that in this cross the dominant color is also in homozygous condition.
When the guinea pigs mate, the resulting progeny will obtain one dominant allele from the dominant color parent and one recessive allele from the recessive color parent. The progeny will be heterozygous and show the dominant phenotype since the dominant allele will mask the recessive allele. Thus, the color which is visible in their offspring will be the dominant color.
The type of mutation that occurred would be base pair deletion.
Brainliest appreciated :D
Answer:
The answer was A
It's a Heterotroph
It's means they eat thing outside of themselves instead of producing their own food.
I believe it's correct
Explanation: