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3 years ago

A number squared then decreased by 15

Mathematics

1 answer:

Snezhnost [94]3 years ago

8 0

Answer:

(x^2) - 15

Step-by-step explanation:

assuming x is the 'number'

number squared = number to the power of 2 = x^2

decreased by 15 = -15

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Find a formula for Y(t) with Y(0)=1 and draw its graph. What is Y\infty?

tino4ka555 [31]

Answer:

$(a)\ y(t)\ =\ -2e^{-2t}+3$

$(b)\ y(t)\ =\ 4e^{-2t}-3$

Step-by-step explanation:

(a) Given differential equation is

Y'+2Y=6

=>(D+2)y = 6

To find the complementary function, we will write

D+2=0

=> D = -2

So, the complementary function can be given by

$y_c(t)\ =\ C.e^{-2t}$

To find the particular integral, we will write

$y_p(t)\ =\ \dfrac{6}{D+2}$

$=\ \dfrac{6.e^{0.t}}{D+2}$

$=\ \dfrac{6}{0+2}$

= 3

so, the total solution can be given by

$y_(t)\ =\ C.F+P.I$

$=\ C.e^{-2t}\ +\ 3$

$y_(0)=C.e^{-2.0}\ +\ 3$

but according to question

1 = C +3

=> C = -2

So, the complete solution can be given by

$y_(t)\ =\ -2.e^{-2.t}\ +\ 3$

(b) Given differential equation is

Y'+2Y=-6

=>(D+2)y = -6

To find the complementary function, we will write

D+2=0

=> D = -2

So, the complementary function can be given by

$y_c(t)\ =\ C.e^{-2t}$

To find the particular integral, we will write

$y_p(t)\ =\ \dfrac{-6}{D+2}$

$=\ \dfrac{-6.e^{0.t}}{D+2}$

$=\ \dfrac{-6}{0+2}$

= -3

so, the total solution can be given by

$y_(t)\ =\ C.F+P.I$

$=\ C.e^{-2t}\ -\ 3$

$y_(0)\ =C.e^{-2.0}\ -\ 3$

but according to question

1 = C -3

=> C = 4

So, the complete solution can be given by

$y_(t)\ =\ 4.e^{-2.t}\ -3$

4 0

3 years ago

Hii! please help asap. i’ll give brainliest

3241004551 [841]

Answer:

Step-by-step explanation:

The numbers you have are 2, 2, 3, 4, 8, 8, 8

First, cross out 2 on the very left and 8 on the very right.

Then you are left with 2, 3, 4, 8, 8, Then cross out the 2 on the left and the 8 on the right, and you are left with 3, 4, 8. Cross out the 3 and 8, and you are left with the median, 4.

If this helps, make sure to rate it 5 stars and give me brainliest and a thanks!

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Marysya12 [62]

Answer:

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