Answer:No i do not recall knowing sorry.
Explanation:
Recall that √x has a domain of x ≥ 0.
So, f(x) is defined as long as
(x + 1)/(x - 1) ≥ 0
• We have equality when x = -1
• Otherwise (x + 1)/(x - 1) is positive if both x + 1 and x - 1 are positive, or both are negative:


Then the domain of f(x) is
x > 1 or x ≤ -1
On the other hand, g(x) is defined by two individual square root expressions with respective domains of
• x + 1 ≥ 0 ⇒ x ≥ -1
• x - 1 ≥ 0 ⇒ x ≥ 1
but note that g(1) is undefined, so we omit it from the second domain.
Then g(x) is defined so long as both x ≥ -1 *and* x > 1 are satisfied, which means its domain is
x > 1
f(x) and g(x) have different domains, so they are not the same function.
It should be one but if I’m wrong I am so so sorry
- AC=Hypotenuse=20
- BC=Base=16
AB:-
Apply Pythagorean theorem





Now
- DE=AB/3=12/3=4
- EF=BC/3=16/3=5.3
- DF=AC/3=20/3=6.6
Now



Answer:
My dad left me at a young age, therefore its 69
Explanation: