Question

Find the diagonal of the rectangular solid.

Answer 1

Answer:

5√2 feet or

7.07 feet to the nearest hundredth.

Step-by-step explanation:

First you need to find the length of a diagonal across the base of the solid.

x^2 = 5^2 + 4^2 = 41

so x = √41.

Now the diagonal of the solid is:

d^2 = 3^2 + (√41)^2 = 9 + 41

d^2 = 50

d = √50 = 5√2 ft.

Answer 2

Answer:

5√2

Step-by-step explanation:

(Diagonal of the floor)² = 5² +  4² = 25 + 16 = 41

Diagonal of the rectangular solid)² = (Diagonal of the floor)² + 3²

                                                         = 41 + 9 = 50

Diagonal of the rectangular solid = $\sqrt{50} = \sqrt{2*5*5}=5\sqrt{2}$