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professor190 [17]
3 years ago
10

A card is drawn from a standard deck, not replaced, and another is drawn. What is the probability of choosing a heart then a spa

de?
Mathematics
1 answer:
Llana [10]3 years ago
5 0

Answer:

49/52

Step-by-step explanation:

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A classroom contains an equal number of boys and girls. If 5 girls leave, twice as many boys and girls remain. What was the orig
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The answer is 10 because 5 x 2 is 10
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How can i learn multiplication in one day
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4 0
3 years ago
3. Is it possible to solve x (t ) for t, substitute it into y(t) to eliminate the parameter, t, and write it as a rectangular eq
Maslowich

Answer: Yes

Step-by-step explanation:

Though x and y can be achieved in a system of equations. The equation

x (t)=0.0411905(t^2)+(-0.164619)t+28.0114

And

y (t)=-0.024127(t^2)+(-0.591143)t+(-87.4403)

Are not system of equations but rather two different models of equations. Nevertheless

To find t in the first equation, x(t) has to be equal to zero.

When the t is substituted in the second equation, t will completely disappear. Given the value of y(t) and vice versa.

8 0
4 years ago
The U.S. National Highway Traffic Safety Administration gathers data concerning the causes of highway crashes where at least one
ZanzabumX [31]

Answer:

probability of a crash with at least one fatality if a driver drives while legally intoxicated (BAC greater than 0.09) = 0.001932

Step-by-step explanation:

P(BAC=0|Crash with fatality)=0.625

P(BAC is between .01 and .09|Crash with fatality)=0.302

P(BAC is greater than .09|Crash with fatality)=0.069

Let the event of BAC = 0 be X

Let the event of BAC between 0.01 and 0.09 be Y

Let the event of BAC greater than 0.09 be Z

Let the event of a crash with at least one fatality = C

P(X|C) = 0.625

P(Y|C) = 0.302

P(Z|C) = 0.069

P(C) = 0.028

probability of a crash with at least one fatality if a driver drives while legally intoxicated (BAC greater than 0.09) = P(C n Z)

But note that the conditional probability of probability that a driver is intoxicated (BAC greater than 0.09) given that there was a crash that involved at least a fatality is given by

P(Z|C) = P(Z n C)/P(C)

P(Z n C) = P(Z|C) × P(C) = 0.069 × 0.028 = 0.001932

Hope this Helps!!!

8 0
3 years ago
Please help me with this question ​
ra1l [238]
The answer would be 18 soldiers!!
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3 years ago
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