Question

Maximize the objective function p = 5x + 3y for the given constraints. X ≥ 0 y ≥ 0 3x + 6y ≤ 48 2x + 8y ≤ 56.

Answer 1

The maximized value of the objective function is 38

The objective function is given as:

Max P = 5x + 3y

The constraints are given as:

• 3x + 6y ≤ 48
• 2x + 8y ≤ 56
• x ≥ 0 y ≥ 0

To do this, we make use of the graphical method.

See attachment for the graph of the constraints.

From the graph, we have the following feasible point

$(x,y) = (4,6)$

Substitute 4 for x and 6 for y in the objective function.

$Max\ P = 5x + 3y$

So, we have:

$P = 5 \times 4 + 3 \times 6$

$P = 20 + 18$

$P = 38$

Hence, the maximized value of the objective function is 38

Read more about objective functions at:

brainly.com/question/16826001