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Gnom [1K]
3 years ago
11

PLEASE HELP!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Dmitriy789 [7]3 years ago
4 0

Answer:

7.11\leq-7.1

Step-by-step explanation:

jeyben [28]3 years ago
4 0

Answer:

Question 1- C. 7.11 > -7.1

Question 2- True

Question 3- -3 < -1 and -3 ≤ -1

Question 4- I don't know

Question 5- {3,4}

Step-by-step explanation:

I ran it through the calculator only on question 4 I didn't know the answer

-Rocketgamer360

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Step-by-step explanation:

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Poly(3-hydroxybutyrate) (PHB), a semicrystalline polymer that is fully biodegradable and biocompatible, is obtained from renewab
navik [9.2K]

Answer:

(a) 2.3

(b) 0.5245

(c) 0.7242

(d) 0.5245

Step-by-step explanation:

The data provided is:

S = {180.5, 181.7, 180.9, 181.6, 182.6, 181.6,  181.3, 182.1, 182.1, 180.3, 181.7, 180.5}

(a)

The formula to compute the sample range is:

\text{Sample Range}=\text{max.}_{x}-\text{min.}_{x}

The data set arranged in ascending order is:

S' = {180.3 , 180.5 , 180.5 , 180.9 , 181.3 , 181.6 , 181.6 , 181.7 , 181.7 ,, 182.1 , 182.1 , 182.6}

The minimum value is, 180.3 and the maximum value is, 182.6.

Compute the sample range as follows:

\text{Sample Range}=\text{max.}_{x}-\text{min.}_{x}

                       =182.6-180.3\\=2.3

Thus, the sample range is 2.3.

(b)

Compute the sample variance as follows:

S^{2}=\frac{1}{n-1}\sum(x_{i}-\bar x)^{2}

     =\frac{1}{12-1}\times [(180.5-181.41)^{2}+(181.7-181.41)^{2}+...+(180.5-181.41)^{2}]\\\\=\frac{1}{11}\times 5.7692\\\\=0.524473\\\\\approx 0.5245

Thus, the sample variance is 0.5245.

(c)

Compute the sample standard deviation as follows:

s=\sqrt{S^{2}}

  =\sqrt{0.5245}\\\\=0.7242

Thus, the sample standard deviation is 0.7242.

(d)

Compute the sample variance using the shortcut method as follows:

S^{2}=\frac{1}{n-1}\cdot [\sum x_{i}^{2}-n(\bar x)^{2}]

     =\frac{1}{12-1}\cdot [394913.57-(12\times (181.41)^{2}]\\\\=\frac{1}{11}\times [394913.57-394907.80]\\\\=\frac{5.77}{11}\\\\=0.5245

Thus, the sample variance is 0.5245.

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