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Bond [772]
2 years ago
7

Heeeeeeeeeeeeeeelpmeeeeeeeeeeeeeeeeeeee

Mathematics
1 answer:
Gemiola [76]2 years ago
3 0

Answer:

5 = length

10 = width

Step-by-step explanation:

Length is 5

width is 10

meets this criteria

width is twice longer than length (check)

equals 30 (check)

also if you add it to the perimeter formula, it works:

l + l + w + w

5 + 5 + 10 + 10 = 30

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Frank bought 791 acres of land for a housing development. If 41 acres of his purchase is reserved for a park, how many five-acre
GalinKa [24]

To solve the question, first we will subtract 41 from 791, and we will get 750. Next, we can divide by 5 to figure out how many lots are for purchase, and we get 150! There are 150 five-acre lots available!

6 0
4 years ago
Prove that sin(x)/1-cos(x) = 2 · csc(x) using trigonometric identities. Show all steps taken.
Gwar [14]

Answer:

Step-by-step explanation:

sin(x) + tan(x)=sin(X) + sin(x)/cos(x)

=sinx(1+1/cosx)

=sinx(1+secx)

=1+secx/cosecx. (Since sinx=1/cosecx)

Hence LHS=RHS proved

7 0
3 years ago
Random variables X Poisson~ ( a) ,Y Poisson ~ ( a) . X and Y are independent. If 2 1, 2 1. U =2X+ Y-1, V=2X- Y +1. Find: ) Cov (
german

By definition of covariance,

\mathrm{Cov}(U,V)=E[(U-E[U])(V-E[V])]=E[UV-E[U]V-UE[V]+E[U]E[V]]=E[UV]-E[U]E[V]

Since U=2X+Y-1 and V=2X-Y+1, we have

E[U]=2E[X]+E[Y]-1

E[V]=2E[X]-E[Y]+1

\implies E[U]E[V]=(2E[X]+E[Y]-1)(2E[X]-(E[Y]-1))=4E[X]^2-(E[Y]-1)^2=4E[X]^2-E[Y]^2+2E[Y]-1

and

UV=(2X+Y-1)(2X-(Y-1))=4X^2-(Y-1)^2=4X^2-Y^2+2Y-1

\implies E[UV]=4E[X^2]-E[Y^2]+2E[Y]-1

Putting everything together, we have

\mathrm{Cov}(U,V)=(4E[X^2]-E[Y^2]+2E[Y]-1)-(4E[X]^2-E[Y]^2+2E[Y]-1)

\mathrm{Cov}(U,V)=4(E[X^2]-E[X]^2)-(E[Y^2]-E[Y]^2)

\mathrm{Cov}(U,V)=4V[X]-V[Y]=4a-a=\boxed{3a}

7 0
4 years ago
-6 x f(3) -6 x g(-1)​
AfilCa [17]

Answer:

-18F + 6g The exact value

4 0
3 years ago
Select all of the expressions that are equivalent to 4 + w + 12w
andrew11 [14]

Answer:

Step-by-step explanation:

the selections that are equivalent to 4 + w + 12:

1st and 3rd

5 0
3 years ago
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